Respuesta :
Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = pi\over4*d^2=pi\over4*0.3^2=0.07 m^2
Thank you for posting your question here at brainly. I hope the answer helps.
Thank you for posting your question here at brainly. I hope the answer helps.
Answer:
[tex]P = 2.77 \times 10^5 Pa[/tex]
Explanation:
As we know that pressure is defined as the ratio of normal force and area
here we know that
normal force is due to weight of the car
[tex]F = mg[/tex]
[tex]F = (2000)(9.8)[/tex]
[tex]F = 19600 N[/tex]
now the area is given as
[tex]A = \pi r^2[/tex]
[tex]A = \pi(0.15)^2[/tex]
[tex]A = 0.0707 m^2[/tex]
Now the pressure is given as
[tex]P = \frac{19600}{0.0707}[/tex]
[tex]P = 2.77 \times 10^5 Pa[/tex]
