we know that
To find the solution let's factor the equation
[tex] x^{2} + 4x - 4 = 8 [/tex]
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex] x^{2} + 4x = 8+4 [/tex]
[tex] x^{2} + 4x = 12 [/tex]
Complete the square. Remember to balance the equation by adding the same constants to each side
[tex] x^{2} + 4x+4 = 12+4 [/tex]
[tex] x^{2} + 4x+4 = 16 [/tex]
Rewrite as perfect squares
[tex] (x+2)^{2} = 16 [/tex]
[tex] (x+2)^{2} = 16\\ (x+2)=(+/-)\sqrt{16} \\ x1=-2+\sqrt{16} =-2+4=2\\ x2=-2-\sqrt{16} =-2-4=-6 [/tex]
therefore
the answer is the option
A. –6 or x = 2
