we have
[tex]3(8-4x)<6(x-5)[/tex]
Eliminate the parenthesis
[tex]24-12x<6x-30[/tex]
Group terms that contain the same variable, and move the constants to the opposite side of the inequality
[tex]24+30<6x+12x[/tex]
[tex]54<18x[/tex]
Divide by [tex]18[/tex] both sides
[tex]54/18<x[/tex]
[tex]3<x[/tex]
rewrite the inequality
[tex]x>3[/tex]
the solution is the interval-------> (3,∞)
The answer in the attached figure
