Answer:
18.78 m/s.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 50 kg
Initial velocity (u) = 0 m/s
Height (h) of cliff = 18 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity with which the diver reach the water can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 18
v² = 0 + 352.8
v² = 352.8
Take the square root of both side
v = √352.8
v = 18.78 m/s
Thus, the diver will reach the water with a velocity of 18.78 m/s.
