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A 15 Kilogram anvil is hung from a ceiling . While it is hanging there , it has been determined to have 65 Joules of gravitational potential energy relative to the floor . If the anvil is released , what would be its speed just before it hits the floor ?

Respuesta :

Answer:

v = 2.94 m/s

Explanation:

Given that,

Mass of anvil, m = 15 kg

The gravitational potential energy relative to the floor, P = 65 J

We need to find the speed just before it hits the floor when the Anvil is released. Let it is v.

We can use the conservation of energy.

[tex]\dfrac{1}{2}mv^2=mgh\\\\65=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{65\times 2}{15}} \\\\v=2.94\ m/s[/tex]

So, the required speed is 2.94 m/s.

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