Answer:
Area of ΔXYZ = n(r * r) square units
Step-by-step explanation:
Sides of ΔABC are 30 units, 40 units and 60 units.
Corresponding sides of another triangle XYZ are r times as long as the sides of ΔABC.
Therefore, sides of ΔXYZ will be, 30r units, 40r units and 60r units.
Perimeter of the triangle XYZ = 30r + 40r + 60r
= 130r units
If the area of ΔABC = n square units
Then the ratio of the area of ΔXYZ and ΔABC = (Ratio of the sides of ΔXYZ and ΔABC)²
[tex]\frac{\text{Area of triangle XYZ}}{\text{Area of triangle ABC}}=(\frac{\text{Side length of XYZ}}{\text{Side length of triangle ABC}})^2[/tex]
[tex]\frac{\text{Area of triangle XYZ}}{n}=(r)^2[/tex]
Area of ΔXYZ = nr² ≈ n(r * r)
Therefore, Option (3) will be the answer.