Given :
A badminton shuttlecock leaves the racquet traveling 30 m/s.
It goes over the net 0.5 seconds later with a speed of 10 m/s.
To Find :
The average acceleration of the shuttlecock.
Solution :
We know, average acceleration(a) is given by :
[tex]a = \dfrac{\text{Change in speed}}{\text{Time taken }}\\\\a = \dfrac{10-30}{0.5 }\ m/s^2\\\\a = -40\ m/s^2[/tex]
Therefore, the average acceleration is -40 m/s².
