Engineering The equation for the cross section of a spotlight is y+5= 1/2x^2.

measured in inches. The bulb is located at the focus. How far is the bulb from the

Vertex of the cross section?

Respuesta :

Answer:

[tex]p=1/2\ or\ 0.5\ inches[/tex]

Step-by-step explanation:

From the question we are told that

Equation of cross section is [tex]y+5= \frac{1}{2x^2}[/tex]

Generally the equation can be rewritten mathematically as

  [tex]y+5= \frac{1}{2}x^2[/tex]

  [tex]x^2=(y+5)2[/tex]

  [tex](x-0)^2=(y-(-5))2[/tex]

Generally the equation of a parabola with vertical axis is mathematically given by

[tex](x - h)2 = 4p(y - k)[/tex]

Therefore  comparing equations

[tex](x-0)^2=(y-(-5))2[/tex]

[tex]4p=2[/tex]

[tex]p=2/4[/tex]

The distance from the bulb to the vertex of the cross section is given by

[tex]p=1/2\ or\ 0.5\ inches[/tex]