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A sculpture is suspended in equilibrium by two cables, one from a wall and the other

from the ceiling of a museum gallery. Cable 1 applies a horizontal force to the right of

the sculpture and has a tension, Fn. Catble 2 applies a force upward and to the left at an

angle of 37.0° to the negative x-axis and has a tension, Fn. The gravitational force on

the sculpture is 5.00 '10`N. What is Fn?

Respuesta :

okpalawalter8

Answer:

[tex]T_1=6655.295917 \approx 6655.3N[/tex]

Explanation:

From the question we are told that

Angle of cable 2 [tex]\theta=37.0\textdegree[/tex]

Weight of sculpture [tex]W=5000 N[/tex]

Generally the Tension from cable 2 [tex]T_2[/tex] is mathematically given by

   [tex]T_2sin37\textdegree=5000N[/tex]

   [tex]T_2=5000N/sin37\textdegree[/tex]

   [tex]T_2=8308.2N[/tex]

Generally the Tension from Cable 1 [tex]T_1[/tex] is mathematically given by

   [tex]T_1=T_2 cos37\textdegree[/tex]

   [tex]T_1=8308.2* cos 37\textdegree[/tex]

   [tex]T_1=6655.295917 \approx 6655.3N[/tex]

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