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A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coefficient of friction of the skis on snow is 0.05, then what is the weight of the skier?

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boffeemadrid

Answer:

[tex]1200\ \text{N}[/tex]

Explanation:

F = Force on the skier = 60 N

[tex]\mu[/tex] = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

[tex]F=\mu w[/tex]

[tex]\Rightarrow w=\dfrac{F}{\mu}[/tex]

[tex]\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}[/tex]

[tex]\Rightarrow w=1200\ \text{N}[/tex]

Weight of the skier on which the force is being applied is [tex]1200\ \text{N}[/tex] .

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