Answer:
1/2(8x-6)=-1/3(9x-12)
We move all terms to the left:
1/2(8x-6)-(-1/3(9x-12))=0
Domain of the equation: 2(8x-6)!=0
x∈R
Domain of the equation: 3(9x-12))!=0
x∈R
We calculate fractions
(3x9/(2(8x-6)*3(9x-12)))+(-(-2x8)/(2(8x-6)*3(9x-12)))=0
We calculate terms in parentheses: +(3x9/(2(8x-6)*3(9x-12))), so:
3x9/(2(8x-6)*3(9x-12))
We multiply all the terms by the denominator
3x9
We add all the numbers together, and all the variables
3x^9
We do not support expression: x^9
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