Answer:
[tex]y=+\frac{2\sqrt{2} }{3}\\[/tex]
Step-by-step explanation:
In the unit circle we have:
[tex]x^{2} +y^{2} =1[/tex]
In the picture we see that x=1/3.
Using de equation of unit circle:
[tex](\frac{1}{3} )^{2} +y^{2} =1\\\\\frac{1+9y^{2} }{9}=\frac{9}{9} \\\\y^{2} =\frac{8}{9} \\\\\sqrt{y^{2}} =\sqrt{\frac{8}{9}}\\\\y=+\frac{2\sqrt{2} }{3}[/tex]
y is positive because y are in the first quadrant of the cartesian plane.
