Answer:
0.8878 mol KClO4
Explanation:
Molar mass of KClO4 = 39.0983 + 35.453 + ( 15.9994 x 4 ) = 39.0983 + 35.453 + 63.9976 = 138.5489g/mol
but,
number of moles = mass in grams / molar mass where mass in grams = 123g, molar mass = 138.5489g/mol
number of moles = 123g / 138.5489g/mol = 0.8878mol
Therefore the number of moles present in 123 g of [tex] KClO_4[/tex] is 0.888 moles.
Given,
The weight of the [tex] KClO_4[/tex] is 123. grams
molecular weight of [tex] KClO_4[/tex] is [tex]39+35.5+16\times4=138.5 g[/tex]
138.5 g of [tex]KclO_4[/tex] is equal to one mole
Gram molecular wt. of a substance is equal to one mole
No. of moles = [tex]\frac{Wt}{GMW} [/tex]
123 g of [tex]KClO_4[/tex] is equal to [tex]\frac{123}{138.5}=0.888 moles [/tex]
Learn More:https://brainly.com/question/2416206
