9514 1404 393
Answer:
1) see below
2) 2.5 inches per day
3) the seed was planted below ground level
4) h = 2.5d -3
Step-by-step explanation:
1) We note that the seedling grew 12-7 = 5 inches in the 2 days between day 4 and day 6. This lets us fill in the numbers for even days by adding or subtracting 5 inches:
day 8 will be 5 inches more than day 6, 17 inches.
day 2 will be 5 inches less than day 4, 2 inches.
day 0 will be 5 inches less than that, -3 inches.
The value for day 3 will be halfway between day 2 and day 4, so will be (2+7)/2 = 4.5 inches.
See the attachment for the complete table.
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2) In one day, the plant grows in/day = 5/2 = 2.5 inches.
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3) If the plant grows at the steady rate of 5 inches in 2 days, it must have been planted 3 inches below ground on day 0.
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4) In question 2, we found the rate per day (slope) to be 2.5. In question 3, we found the "y-intercept" to be -3. Then the slope-intercept equation with independent variable d and dependent variable h is ...
h = 2.5d -3
