Required Answer:-
This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.
By Pythagoras theoram,
[tex] {p}^{2} + {b}^{2} = {h}^{2} [/tex]
where p is the perpendicular, b is the base and h is the hypotenuse.
Plugging the values,
[tex] {9}^{2} + {11}^{2} = {h}^{2} [/tex]
Then,
[tex]h = \sqrt{ {9}^{2} + {11}^{2} } [/tex]
[tex]h = 14.12(approx.)[/tex]
Hence:-
The x of the right angled ∆ = 14.12
