Answer:45
Step-by-step explanation:
Given
at t=0 there are 4 unpaired socks
Suppose at any instant no of unpaired socks are [tex]N=4e^{kt}[/tex]
at t=4(months)
[tex]N=9=4e^{4k}\\e^{4k}=\frac{9}{4}[/tex]
for t=12(months)
[tex]N=4e^{12k}=4(e^{4k})^{3}[/tex]
[tex]N=4\times (\frac{9}{4})^3=\frac{9^3}{4^2}\\N=45.56\approx 45\ \text{unpaired socks}[/tex]
