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Weighing 15,000 N is parked on a 10 m2 hydraulic lift platform. What is the area of ​​a small piston if a 1,100 N nozzle is used to lift the vehicle?

Respuesta :

Answer:

[tex]A_2=0.74\ m^2[/tex]

Explanation:

Given that,

Weight, F₁ = 15,000 N

Area, A₁ = 10 m²

Weight, F₂ = 1100 N

We need to find the area of the small piston. The pressure exerted on both piston will be equal such that,

[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\A_2=\dfrac{F_2A_1}{F_1}\\\\A_2=\dfrac{1100\times 10}{15000}\\\\A_2=0.74\ m^2[/tex]

So, the area of the smaller piston is [tex]0.74\ m^2[/tex].

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