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Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line

(dont think u can graph so its okay)

Write an equation in pointslope form of the line having the given slope that contains the given point then graph the line dont think u can graph so its okay class=

Respuesta :

Answer:

[tex]y=-\frac{5}{3}x-3[/tex]

Step-by-step explanation:

Equation of straight line in point slope form is given a s

[tex](y-y_1)=m(x=x_1)[/tex]

Here

[tex]m=-\frac{5}{2} \ and\ (x_1, y_1)=(0, -3)[/tex]

[tex](y+3)=-\frac{5}{3}(x-0)[/tex]

[tex]y=-\frac{5}{3}x-3[/tex]