In AABC, m LACB 90°, CD I AB and m LACD -45°. Find:
Find CD, if BC = 3 in
459
B В
D

Answer:
CD = (3√2)/2 = 2.12 in.
Step-by-step explanation:
Reference angle = m<BCD = 45°
Hypotenuse = BC = 3 in.
Adjacent side = CD = ??
Apply trigonometric ratio
Cos(45) = CD/3
Multiply both sides by 3
3*Cos(45) = CD
3*√2/2 = CD (cos 45 = √2/2)
(3√2)/2 = CD
CD = (3√2)/2 = 2.12