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Two students are playing catch with a 0.20 kg baseball. The first student throws the ball at 25 m/s. How much work is done by the second student in stopping the ball?

Respuesta :

Answer:

W = 62.5 J

Explanation:

Given that,

Mass of a baseball, m = 0.2 kg

Initial speed of first student, u = 25 m/s

Finally, the ball stops, v = 0

We need to find the work done by the second student in stopping the ball. We know that, work done is equal to the change in kinetic energy. It can be given by :

[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\W=-\dfrac{1}{2}mu^2\\\\W=-\dfrac{1}{2}\times 0.2\times(25)^2\\\\W=-62.5\ J[/tex]

So, the required work done is 62.5 J.

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