Answer:
Explanation:
From the given information:
The gravitational potential energy at A is:
[tex]PE_A = mgh[/tex]
GIven that:
mass(m) = 3
height (h) = 3
[tex]PE_A =3\times 9.81 \times 3[/tex]
[tex]\mathbf {PE_A =88.29 \ J }[/tex]
b)
Using the conservation of mechanical energy:
[tex]PE_A+KE_A = PE_B + KE_B[/tex]
[tex]88.29 +0 = 3(9.8)(1) + KE_B[/tex]
[tex]88.29 = 29.4 + KE_B[/tex]
[tex]KE_B = 88.29 -29.4[/tex]
[tex]\mathbf{ KE_B= 58.89 \ J}[/tex]
From the data provided and the calculations done, the potential energy at A is 88.3 J while the kinetic energy at B is 58.9 J.
The potential energy of a body is given as:
where:
m = mass of the object
g = acceleration due to gravity
h = h
At A:
m= 3.0 kg
g = 9.8 m/s^2
h = 3.0 m
PE = 3 × 9.8 × 3
PE = 88.3 J
Kinetic energy, KE of a body is given as:
where:
From the law of conservation of energy, the sum of potential energy and Kinetic energy at every point is equal.
PE + KE at A = PE + KE at B
KE at B = PE + KE at A - PE at B
At A, PE = 88.3 J and KE = 0
At B; h = 1.0 m
PE = 3 × 9.8 × 1
PE = 29.4 J
Therefore, KE at B = 88.3 + 0 - 29.4
KE at B = 58.9 J
Therefore, the potential energy at A is 88.3 J while the kinetic energy at B is 58.9 J.
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