In a survey of school students, 64 had taken mathematics course, 94 had taken chemistry course, 58 had taken physics course, 28 had taken mathematics and physics, 26 had taken mathematics and chemistry, 22 had taken chemistry and physics course, and 14 had taken all the three courses. Find how many had taken one course only by using Venn diagram.

A Venn diagram exists as an illustration that utilizes circles to illustrate the relationships among things or finite groups of things. Circles that overlap include a commonality while circles that do not overlap do not share those traits. Venn diagrams permit visually illustrating the similarities and contrasts between two concepts.

Let M =sets of students who had taken mathematics

C= sets of students who had taken chemistry

P= represent sets of students who had taken physics

From the given information, we have

n(M) = 64 , n(C) = 94, n(P) = 58,

n(MnP) = 28, n(MnC) = 26, n(CnP) = 22

n(MnCnP) = 14

No. of students who had taken only Math :

= n(M) - [n(MnP) + n(MnC) - n(MnCnP)]

= 64 - [28+26-14]

= 64 - 40

= 24

No. of students who had taken only Chemistry

= n(C) - [n(MnC) + n(CnP) - n(MnCnP)]

= 94 - [26+22-14]

= 94 - 34

= 60

No. of students who had taken only Physics

= n(P) - [n(MnP) + n(CnP) - n(MnCnP)]

= 58 - [28+22-14]

= 58 - 36

= 22

Total no. of students who had taken only one course

= 24 + 60 + 22

= 106

To learn more about Venn diagram refer to:

https://brainly.com/question/2099071

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