Kiara invested $3,500 into two accounts. One account paid 5% interest and the other paid 7.5% interest. She earned 6%
interest on the total investment. How much money did she put in each account?

Respuesta :

Answer:

A=$2100

B=$1400

Step-by-step explanation:

3500*1.06=3710

a+b=3500

1.05a+1.075b=3710

1.05a+1.05b=3675

1.05a+1.075b=3710

Subtract 1.05a+1.05b=3675 from 1.05a+1.075b=3710

0.025b=35

b=1400

a=3500-1400=2100

Double check: (2100*1.05)+(1400*1.075)=3710

3500*1.06=3710

The amount invested in the account that pays a 5% interest is $2100 and the amount invested in the account that pays a 7.5% interest is $1400.

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

0.05a + 0.075b = (0.06 x $3500)

0.05a + 0.075b = $210 ----- equation 1

a + b = $3,500   -------- equation 2

Where:

a is the amount invested in the account that paid a 5% interest.

b is the amount invested in the account that paid a 7.5% interest.

The amount invested in the account that pays a 7.5% interest.

In order to determine this value, multiply equation 2 by 0.05

0.05a + 0.05b = 175  ------- equation 3

0.025b = 35

b = $1400

The amount invested in the account that pays a 5% interest.

a + $1400 = $3500

a = $3500 - 1400

a = $2100

Therefore, The amount invested in the account that pays a 5% interest is $2100 and the amount invested in the account that pays a 7.5% interest is $1400.

Learn more about equations here;

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