Answer:
P₄ + 4NaOH + 2H₂O → 2PH₃ + 2Na₂HPO₃
Explanation:
The given reaction expression is given as:
P₄ + NaOH + H₂O → PH₃ + Na₂HPO₃
To solve this problem, now we put coefficients a, b, c, d and e and we use a mathematical approach to solve this problem;
aP₄ + bNaOH + cH₂O → dPH₃ + eNa₂HPO₃
Conserving P: 4a = d + e
Na: b = 2e
O: b + c = 3e
H: b + 2c = 3d + e
let b = 1, e = [tex]\frac{1}{2}[/tex] , c = [tex]\frac{1}{2}[/tex], d = [tex]\frac{1}{2}[/tex], a = [tex]\frac{1}{4}[/tex]
Multiply through by 4;
b = 4, e = 2, c = 2, d = 2, a = 1
P₄ + 4NaOH + 2H₂O → 2PH₃ + 2Na₂HPO₃
