Respuesta :
Answer:
the statement is false for any value of x
Step-by-step explanation:
Answer:
[tex] \boxed{ x < 0}[/tex]
Step-by-step explanation:
[tex]if \to : \\ 3(1 – 2x) > 3 – 6x \\ then \to : \\ 3(1 – 2x) > 3 – 6x = \\ 3 - 6x > 3 - 6x = \\ - 3 + 3 > - 6x + 6x \\ 0 > x( -6 + 6) \\ 0 > x(0) \\ x < \frac{0}{0} \\ \boxed{ x < 0}[/tex]