Respuesta :

Answer:

[tex]\underline{\boxed{s_a = 72}}[/tex]

Step-by-step explanation:

[tex]first \to : \underline{\boxed{am \: smart}} \: next \to : \\ let \: the \: total \: area \: be \to \: t_a = 132 \\ let \: the \: shaded \: area \: be \to \: s_a = ? \\ let \: the \: unshaded \: area \: be \to \: u_a =l \times b \\but \to : \\ t_a = s_a + u_a \\ s_a = t_a - u_a \\ s_a = 132 - (l \times b) \\ s_a = 132 - (6 \times 10) \\ s_a = 132 - 60 \\ \boxed{s_a = 72}[/tex]