Answer:
[tex]16\ \text{units}[/tex]
Step-by-step explanation:
[tex]WV=13\ \text{units}[/tex]
[tex]WY=17\ \text{units}[/tex]
[tex]\angle VWY=64^{\circ}[/tex]
[tex]VY=x[/tex]
From cosine rule we have
[tex]x=\sqrt{WV^2++WY^2-2WV\times WY\cos \angle VWY}\\\Rightarrow x=\sqrt{13^2+17^2-2\times 13\times 17\times \cos 64^{\circ}}\\\Rightarrow x=16.25\approx 16\ \text{units}[/tex]
Length of [tex]x[/tex] is [tex]16\ \text{units}[/tex].
