Answer:
0.012 seconds
Explanation:
The time at which the soccer player maintain contact with the ball is as follows:
Given that
Change in momentum = 11 kg.m.s^-1
The Net force applied = F = 910 N
Now the following formulas should be applied:
For acceleration:
[tex]a = \frac{\triangle v}{\triangle t} \\\\\triangle v = a \triangle t[/tex]
For momentum
[tex]\triangle p = m\triangle v\\\\\triangle p = ma\triangle t\\\\\triangle p = f\triangle t\\\\\triangle t = \frac{\triangle p}{F}[/tex]
Now
Put the values to the above formula
= 11 ÷ 910
= 0.012 seconds
