Answer:
2.0 mol C₆H₁₂O₆
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
- Set up: [tex]\displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})[/tex]
- Divide: [tex]\displaystyle 1.99269 \ mol \ C_6H_{12}O_6[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆
