Answer:
[tex]40\ \text{inches}[/tex]
Step-by-step explanation:
[tex]\theta[/tex] = Angle = [tex]5.7^{\circ}[/tex]
Let the vertical distance be is [tex]y=4\ \text{inches}[/tex]
horizontal distance be [tex]x[/tex]
So, slope is the tangent of the angle between the vertical and horizontal
[tex]\dfrac{y}{x}=\tan\theta\\\Rightarrow \tan5.7^{\circ}=\dfrac{4}{x}\\\Rightarrow x=\dfrac{4}{\tan5.7^{\circ}}\\\Rightarrow x=40.07\approx 40\ \text{inches}[/tex]
The horizontal distance for flared sides is [tex]40\ \text{inches}[/tex].
The horizontal distance for flared sides with a 4 inch vertical distance is 40.1 inches
Represent the horizontal distance with h, and the vertical distance with v.
The ratio of the vertical to the horizontal distance is given as: 5.7 degrees.
This means that:
[tex]\tan(5.7) = \frac{v}{h}[/tex]
Make h the subject
[tex]h = \frac{v}{\tan(5.7)}[/tex]
The vertical distance is given as 4 inches.
So, we have:
[tex]h = \frac{4}{\tan(5.7)}[/tex]
Evaluate tan(5.7)
[tex]h = \frac{4}{0.0998}[/tex]
Divide
[tex]h = 40.1[/tex]
Hence, the horizontal distance is 40.1 inches
Read more about vertical and horizontal distances at:
https://brainly.com/question/11956731
