57.5% is the per cent of sodium in sodium hydroxide.
27.89 g of sodium are there in 48.5 g of sodium hydroxide.
What are moles?
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
1. Determination of the percentage of sodium in sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
Percentage of Na = mass of Na / Molar mass of NaOH × 100
Percentage of Na = 23/40 × 100
Percentage of Na = 57.5%
2. Determination of the mass of sodium in 48.5 g of sodium hydroxide.
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Mass of Na in NaOH = 23 g
The total mass of NaOH = 48.5 g
Mass composition of Na = mass of Na / Molar mass of NaOH × Total mass
Mass composition of Na = 23/40 × 48.5
Mass composition of Na = 27.89 g
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