Answer:
Step-by-step explanation:
It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive
The minimum/maximum value of a quadratic function is the vertex, which is at:
For the given function y = x² -10x + 31, the vertex is:
- x = - (-10)/2*1 = 10/2 = 5
The value of y at this point is:
- y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6
The point is
