Given:
The equation is
[tex]3x+4y=24[/tex]
To find:
The x- and y-intercepts of the given equation.
Solution:
We have,
[tex]3x+4y=24[/tex]
Putting x=0, we get
[tex]3(0)+4y=24[/tex]
[tex]0+4y=24[/tex]
[tex]y=\dfrac{24}{4}[/tex]
[tex]y=6[/tex]
Therefore, the y-intercept of the given equation is 6.
Putting y=0, we get
[tex]3x+4(0)=24[/tex]
[tex]3x+0=24[/tex]
[tex]x=\dfrac{24}{3}[/tex]
[tex]x=8[/tex]
Therefore, the x-intercept of the given equation is 8.
