A bag contains counters that are red, black , or green . 1/3 of the counters are red 1/6 of the counters are black There are 15 green counters in the bag. How many black counters are in the bag ?
i’ll give brainliest;)

Respuesta :

Answer:

Number of black counters = 5

Step-by-step explanation:

Let,

x be the total number of counters

Number of red counters = [tex]\frac{1}{3}x[/tex]

Number of black counters = [tex]\frac{1}{6}x[/tex]

Number of green counters = 15

Now,

Red counters + Black counters + Green counters = Total counters

[tex]\frac{1}{3}x+\frac{1}{6}x+15=x\\\\\frac{2x+x+90}{6}=x\\\\3x+90 = 6x\\90 = 6x-3x \\90 = 3x\\3x = 90[/tex]

Dividing both sides by 3

[tex]\frac{3x}{3}=\frac{90}{3}\\x=30[/tex]

Number of black counters = [tex]\frac{1}{6}*30[/tex] = 5

Hence,

Number of black counters = 5