Find the values of x and y . Then find the measures of the interior angles of the polygon.

Step-by-step explanation:
It is a cyclic quadrilateral.
The sum of interior angles of this polygon is equal to 180 degrees.
ATQ,
2x+26y=180
x+13y=90 ....(1)
3x+21y=180
x+7y=60 ....(2)
Subtract equation (1) from (2).
x+7y-(x+13y) = 60-90
x+7y-x-13y=-30
-6y=-30
y = 5
Put the value of y in equation (1
x+13(5) = 90
x+65=90
x = 90-65
x = 25
So,
∠DAB = 26y = 26(5) = 130°
∠ABC = 3x = 3(25) = 75°
∠BCD = 2x = 2(25) = 50°
∠ADC = 21y = 21(5) = 105°
x = 25, y = 5
m∠DAB = 26(y) = 180°
m∠ABC = 3x = 75°
m∠BCD = 2x = 50°
m∠ADC = 21y = 105°
From the picture attached,
By using the property of cyclic quadrilateral,
m∠A + m∠C = 180°
26y + 2x = 180
13y + x = 90 --------(1)
m∠B + m∠D = 180°
3x + 21y = 180
x + 7y = 60 --------(2)
Subtract equation (2) from (1),
(13y + x) - (x + 7y) = 90 - 60
6y = 30
y = 5
Substitute y = 5 in equation (1),
13(5) + x = 90
x = 90 - 65
x = 25
Substitute the values of 'x' and 'y' to get the measures of the angles,
m∠DAB = 26(y) = 180°
m∠ABC = 3x = 75°
m∠BCD = 2x = 50°
m∠ADC = 21y = 105°
Therefore, values of the variables will be,
x = 25, y = 5
m∠DAB = 26(y) = 180°
m∠ABC = 3x = 75°
m∠BCD = 2x = 50°
m∠ADC = 21y = 105°
Learn more about the cyclic quadrilateral here,
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