Respuesta :
Answer: The time after which the concentration of [tex]SO_2Cl_2[/tex] fall to 12.5% of its initial value is 26.2 hours
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant = 100
a - x = amount left after decay process = 12.5
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{8.75hour}=0.0792hour^{-1}[/tex]
b) for concentration to fall to 12.5 % of initial value
[tex]t=\frac{2.303}{0.0792}\log\frac{100}{12.5}[/tex]
[tex]t=26.2hours[/tex]
The time after which the concentration of [tex]SO_2Cl_2[/tex] fall to 12.5% of its initial value is 26.2 hours
