I really need help with this Triangle problem.

Answer:
12
Step-by-step explanation:
Here we use SOHCAHTOA
Seeing as we have the hypotenuse and we are working to find out the opposite, we use SOH
Sin(x)= Opposite/Hypotenuse
Sin(45) = x/[tex]12\sqrt{2} \\[/tex]
×12 root 2
sin(45) times 12 root 2= 12
x=12