A box contains 4 red marbles, 3 green marbles and 2 blue marbles. One marble is removed from the box and it is NOT replaced. Another marble is drawn from the box. What is the probability that the first marble is blue and the second marble is green?

Respuesta :

The required probability is [tex]\dfrac{1}{12}[/tex].

Important information:

  • Red marbles = 4
  • Green marbles = 3
  • Blue marbles = 2

Probability:

Total number of marbles is:

[tex]4+3+2=9[/tex]

The probability of getting a blue marble is [tex]\frac{2}{9}[/tex].

After removing a marble, the number of remaining marbles is 8. So, the probability of getting a green marble is [tex]\frac{3}{8}[/tex].

Now, the probability that the first marble is blue and the second marble is green is:

[tex]P=\dfrac{2}{9}\times \dfrac{3}{8}[/tex]

[tex]P=\dfrac{1}{12}[/tex]

Therefore, the required probability is [tex]\dfrac{1}{12}[/tex].

Find out more about 'Probability' here:

https://brainly.com/question/10697254

Otras preguntas