Answer:
Please check the explanation.
Step-by-step explanation:
Given the system of equations
2 + 2y = 6
2x - 3y = 26
Let us solve the system of equations
[tex]\begin{bmatrix}2+2y=6\\ 2x-3y=26\end{bmatrix}[/tex]
Rearrange equations
[tex]\begin{bmatrix}-3y+2x=26\\ 2y=4\end{bmatrix}[/tex]
Multiply -3y+2x=26 by 2: -6y+4x=52
Multiply 2y = 4 by 3: 6y = 12
[tex]\begin{bmatrix}-6y+4x=52\\ 6y=12\end{bmatrix}[/tex]
adding the equations
[tex]6y=12[/tex]
[tex]+[/tex]
[tex]\underline{-6y+4x=52}[/tex]
[tex]4x=64[/tex]
Solve 4x = 64 for x
[tex]4x = 64[/tex]
divide both sides by 4
[tex]\frac{4x}{4}=\frac{64}{4}[/tex]
Simplify
[tex]x = 16[/tex]
For -6y+4x = 52 plug in x = 16
[tex]-6y+4\cdot \:16=52[/tex]
Multiply the numbers: 4 · 16 = 64
[tex]-6y+64=52[/tex]
Subtract 64 from both sides
[tex]-6y+64-64=52-64[/tex]
Simplify
[tex]-6y=-12[/tex]
Divide both sides by -6
[tex]\frac{-6y}{-6}=\frac{-12}{-6}[/tex]
[tex]y=2[/tex]
Therefore, the solution to the system of equations be:
[tex]y=2,\:x=16[/tex]
Thus,
(x, y) = (16, 2)
Please note that it seems your answer choices have not included the correct option.
Answer:
(10 -2)
Step-by-step explanation:
first you have to substitute the value of x, solve that, substitute the value of y, solve, and that’s about it. :)
