2. Lin’s family buys 2 adult tickets and 2 child tickets for $26. Mike’s family buys 2 adult tickets and 3 child tickets for $31. Which system represents the situation? PLEASE HELP , no one ever helps please if u do pls!
the adult tickets are 8 dollars and they kid tickets are 5 dollars bc 8+8+5+5=26 and mike's family is 8+8+5+5+5=31 hopes this help so each adult ticket is 8 dollars and each kid ticket is 5 dollars
The cost of an adult ticket is $15.50 and the cost of a child ticket is $8.50 Proof: Set up a system of equations calling Adults a and Children c 2a+3c= $56.50 (equation 1) 4c+a= $49.50 (equation 2) a= -4c+49.50 (i subtracted 4c to both sides) (label equation 3) sub equation 3 into equation 1 2(-4c+49.50)+3c= 56.50 -8c+99+3c=56.50 -5c+99=56.50 -99 -99 -5c = -42.50 c= -42.50/ -5 c= 8.50 sub c=8.50 into equation 3 to find adult price a= -4(8.5)+49.50 a= 15.50
Therefore Child Cost = $8.50 and Adult Cost= $15.50
