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5.
A badminton shuttlecock leaves the racquet traveling 30 m/s. It goes over the net 0.5
seconds later with a speed of 10 m/s. Calculate its average acceleration.

Respuesta :

Answer:

[tex]a=40\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a shuttlecock, u = 30 m/s

Final speed of the shuttlecock, v = 10 m/s

Time, t = 0.5 s

We need to find its average acceleration. The acceleration of an object is equal to the change in speed divided by time taken. It is given by :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{10-30}{0.5}\\\\a=-40\ m/s^2[/tex]

So, the average acceleration of badminton shuttlecock is [tex]40\ m/s^2[/tex].

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