Answer:
see explanation
Step-by-step explanation:
Using the chain rule along with standard derivatives
Given
y = f(g(x)) , then
[tex]\frac{dy}{dx}[/tex] = f'(g(x)) × g'(x)
[tex]\frac{d}{dx}[/tex] (sinx) = cosx , [tex]\frac{d}{dx}[/tex] (cosx) = - sinx
(a)
y = sin x²
[tex]\frac{dy}{dx}[/tex] = cos x² × [tex]\frac{d}{dx}[/tex] (x² )
= cos x² × 2x
= 2xcosx²
(b)
y = cos4x³
[tex]\frac{dy}{dx}[/tex] = - sin4x³ × [tex]\frac{d}{dx}[/tex] (4x³ )
= - sin4x³ × 12x²
= - 12x²sin4x³
