The number of different ways this can be done is 6 ways
Permutation and combination
Give the following students Hunter, Gavin, and Levi, line up one behind the other. They can line up in any form as they wish.
In order to line them up as they wish, we will take the factorial of the total student. In general;
n! = n(n-1)!
Since there are 3 students, the different ways can they stand in line is;
3! = 3 * 3 * 1
3! = 6
Hence the number of different ways this can be done is 6 ways
Learn more on permutation here: https://brainly.com/question/12468032
