Answer:
The acceleration during this launch is approximately 31.583 meters per square second.
Explanation:
Let suppose that the ballerina rotates at constant rate. The radial acceleration of the toe at the end of the horizontally extended leg of the ballerina doing a pirouette ([tex]a_{r}[/tex]), measured in meters per square second, is determined by the following formula:
[tex]a_{r} = \frac{4\pi^{2}\cdot r }{T^{2}}[/tex] (1)
Where:
[tex]r[/tex] - Radius, measured in meters.
[tex]T[/tex] - Period, measured in seconds.
If we know that [tex]r = 0.80\,m[/tex] and [tex]T = 1\,s[/tex], then the radial acceleration of the ballerina is:
[tex]a_{r} = \frac{4\pi^{2}\cdot (0.80\,m)}{1\,s}[/tex]
[tex]a_{r} \approx 31.583\,\frac{m}{s^{2}}[/tex]
The acceleration during this launch is approximately 31.583 meters per square second.
