Answer:
[tex]292683[/tex]
Explanation:
Thickness of a piece of paper = 0.0072 cm
Radius of an atom = [tex]1.23\ \AA[/tex]
Conversion factor of [tex]\AA[/tex] to [tex]\text{cm}[/tex] is
[tex]1\ \AA=1\times 10^{-10}\ \text{m}=1\times 10^{-8}\ \text{cm}[/tex]
Diameter of an atom = [tex]2\times 1.23\times 10^{-8}=2.46\times 10^{-8}\ \text{cm}[/tex]
Number of atoms in one piece of paper is
[tex]\dfrac{0.0072}{2.46\times 10^{-8}}=292682.92\approx 292683[/tex]
Hence, the number of atoms in one piece of paper is [tex]292683[/tex].
