Respuesta :
Answer:
E. Assuming that the mean amount of grass eaten by cows is equal to the mean amount of grass eaten by horses, the probability of observing a test statistic of at least 1.664 is 0.0487
Step-by-step explanation:
Given that :
Test statistic, t = 1.064
P-value = 0.0487
Hypothesis : To test if grazing cows eat more grass than grazing horses
The null hypothesis will be :
H0 : μ1=μ2 (that is there is no difference on the mean number of grass eaten by cows and horses).
Alternative hypothesis ; H1 : μ1 > μ2
The null is assumed true unless tested otherwise, the P-value is used as a probability metric for the rejection or acceptance of the null.
Therefore, if the null is True in this scenario, then, the probability of observing a test statistic of at least 1.664 is 0.0487
If the null is true in this scenario, then the probability of observing a test statistic of at least 1.664 is 0.0487.
What are null hypotheses and alternative hypotheses?
In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.
Test statistics, t = 1.064
P-value = 0.0487
The null hypothesis will be
H₀: μ₁ = μ₂ (There is no difference in the mean number of grass eaten by cows and horses)
An alternative hypothesis will be
Hₐ: μ₁ > μ₂
The null is assumed true unless tested otherwise, the P-value is used as a probability metric for the rejection or acceptance of the null.
Therefore, if the null is true in this scenario, then the probability of observing a test statistic of at least 1.664 is 0.0487.
More about the null hypotheses and alternative hypotheses link is given below.
https://brainly.com/question/9504281