Answer:
[tex]P(A\ or\ B) = \frac{1}{50}[/tex]
Step-by-step explanation:
Represent the event that you win with A and the even that your friend win with B.
So, we have:
[tex]P(A) = \frac{1}{100}[/tex]
[tex]P(B) = \frac{1}{100}[/tex]
Required
Calculate P(A or B)
Both events are mutually exclusive.
So:
[tex]P(A\ or\ B) = P(A) + P(B)[/tex]
Substitute values for P(A) and P(B)
[tex]P(A\ or\ B) = \frac{1}{100} + \frac{1}{100}[/tex]
Take LCM
[tex]P(A\ or\ B) = \frac{1+1}{100}[/tex]
[tex]P(A\ or\ B) = \frac{2}{100}[/tex]
Simplify:
[tex]P(A\ or\ B) = \frac{1}{50}[/tex]
