It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of 390 m the field has magnitude 60.0 N/C. At an altitude of 240 m, the magnitude is 100 N/C. Find the net amount of charge contained in a cube 150 m on edge, with horizontal faces at altitudes of 240 and 390 m. Neglect the curvature of Earth.

Respuesta :

Answer:

[tex]q=7.965*10^-^6C[/tex]

Explanation:

From the question we are told that

Altitude of  [tex]d_1 390m[/tex]

Magnitude[tex]M_1=60.0 N/C[/tex]

Altitude of [tex]d_2=240 m[/tex]

Magnitude is [tex]M_2= 100 N/C[/tex]

Distance of cube [tex]d_c=150 m[/tex]

Generally the flux [tex]\phi[/tex] is mathematical given as

 [tex]\phi=60(150)^2cos180+100(150)^2*cos0[/tex]

 [tex]\phi=-9*10^5[/tex]

Generally Quantity of charge  q is mathematically given as

 [tex]q=\varepsilon _0 *\phi[/tex]

 [tex]q=8.85*10^-^1^2 *9*10^5[/tex]

 [tex]q=7.965*10^-^6C[/tex]