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Write a program named BinaryToDecimal.java that reads a 4-bit binary number from the keyboard as a string and then converts it into decimal. For example, if the input is 1100, the output should be 12. (Hint: break the string into substrings and then convert each substring to a value for a single bit. If the bits are b0, b1, b2, b3, then decimal equivalent is 8b0 4b1 2b2 b3)

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Answer:

import java.util.*;

public class BinaryToDecimal

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    String binaryNumber;

    int decimalNumber = 0;

   

 System.out.print("Enter the binary number: ");

 binaryNumber = input.nextLine();

 

 for(int i=0; i<binaryNumber.length(); i++){

     char c = binaryNumber.charAt(binaryNumber.length()-1-i);

     int digit = Character.getNumericValue(c);

     decimalNumber += (digit * Math.pow(2, i));

 }

 System.out.println(decimalNumber);

}

}

Explanation:

Create a Scanner object to be able to get input from the user

Declare the variables

Ask the user to enter the binaryNumber as a String

Create a for loop that iterates through the binaryNumber. Get each character using charAt() method. Convert that character to an integer value using Character.getNumericValue(). Add the multiplication of integer value and 2 to the power of i to the decimalNumber variable (cumulative sum)

When the loop is done, print the decimalNumber variable

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