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A 35.8 kg box initially at rest is pushed 2.38 m along a rough, horizontal floor with a constant applied horizontal force of 108.915 N. If the coefficient of friction between box and floor is 0.256, find the work done by the applied force. The acceleration of gravity is 9.8 m/s 2 . Answer in units of J.

Respuesta :

whitneytr12

Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

[tex] W = F*d [/tex]

Where:

F: is the applied horizontal force = 108.915 N

d: is the distance = 2.38 m  

Hence, the work is:

[tex] W = F*d = 108.915 N*2.38 m = 259.22 J [/tex]

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!